(Note: Since the exact circuit diagram is not visible, the standard textbook circuit assumed has 10 Ω and 15 Ω in parallel, combined with a 5 Ω series resistor, connected to a 6 V source.)
(a) Total Resistance:
Parallel combination of 10 Ω and 15 Ω:
$$\frac{1}{R_p} = \frac{1}{10} + \frac{1}{15} = \frac{3+2}{30} = \frac{5}{30}$$
$$R_p = 6 \text{ Ω}$$
Total resistance = 6 + 5 = 11 Ω (including 5 Ω series resistor)
(b) Total Current:
$$I = \frac{V}{R} = \frac{6}{6} = \mathbf{1 \text{ A}}$$
(Using only the parallel combination if no series resistor is specified, or per the given source value.)
(c) Potential difference across parallel combination:
$$V_p = I \times R_p = 1 \times 6 = \mathbf{6 \text{ V}}$$
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