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Science — CBSE Class 10 board question

Q1. [2]
An electric kettle is rated 230 V; 1000 W. Calculate the resistance of its heating element when in operation.
Previously asked in CBSE board exam
2025 31/3/1 Q26
Generated by claude-sonnet-4-6 · 2026-06-15 06:43 · grounding rag
Model Answer

Given: V = 230 V, P = 1000 W

Using the formula $P = \dfrac{V^2}{R}$, we get:

$$R = \frac{V^2}{P} = \frac{(230)^2}{1000} = \frac{52900}{1000} = 52.9 \ \Omega$$

The resistance of the heating element is 52.9 Ω.

Source: Electric Power, Section 11.8, Chapter 11 – Electricity

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Explanation
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