(i)
Type of image: When the object (candle) is between the pole and focus, the image formed by a concave mirror is virtual, erect, and enlarged.
Change as candle moves away from pole:
Ray diagram (object at C, i.e., u ≈ R):
```
C F P
←————|————|————|
\ /|
\/ |
Object ↑ ↑ Image (at C, same size, real, inverted)
```
(Two rays: one parallel to principal axis reflects through F; one through C reflects back on itself — image forms at C, real, inverted, same size.)
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(ii)
Given: f = +3.0 m (convex mirror), u = –6.0 m
Mirror formula: $\dfrac{1}{v} + \dfrac{1}{u} = \dfrac{1}{f}$
$$\frac{1}{v} = \frac{1}{f} - \frac{1}{u} = \frac{1}{3} - \frac{1}{-6} = \frac{1}{3} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2}$$
$$v = +2 \text{ m}$$
The image is formed 2 m behind the mirror; it is virtual and erect.
---