Answer the following about refraction through three media.
Generated by claude-sonnet-4-6 · 2026-06-15 06:51 · grounding rag
Model Answer
(a)
From the diagram, the ray bends towards the normal entering Medium B, then bends away from the normal entering Medium C, and the ray in C is parallel to the ray in A (like a glass slab).
(i) Speed of light: Speed in A > Speed in C > Speed in B
(ii) Optical density: Medium B is optically densest, Medium A is rarest, and C is intermediate. So: $n_B > n_C > n_A$
Justification (speed): The refractive index of medium 2 w.r.t. medium 1 is $n_{21} = \dfrac{v_1}{v_2}$. A higher refractive index means lower speed. Since $n_B$ is highest, light travels slowest in B. Since $n_C > n_A$, light travels faster in A than in C.
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(b)
(i) When the ray falls obliquely on Medium B, which is optically denser than both A and C:
- At the A–B boundary: ray bends towards the normal (entering denser medium).
- At the B–C boundary: ray bends away from the normal (entering rarer medium).
- The emergent ray in C is not parallel to the incident ray in A (since A and C have different optical densities).
(Diagram: ray bends toward normal at top surface, bends away at bottom, with different angles in A and C.)
(ii) When the ray falls normally (perpendicularly) on Medium B:
- The ray passes straight through without bending at either surface.
- There is no change in direction at any boundary.
(Diagram: straight, undeviated ray passing through all three media.)
Source: Chapter 9, Sections 9.3, 9.3.1, 9.3.2
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Explanation
- For part (a), the key is reading the diagram: the ray bends toward the normal going into B (so B is densest), and the emergent ray in C is parallel to A (as in a glass slab), which means C's density is intermediate. Link speed and optical density using $n = v_1/v_2$.
- For part (b)(i), since A and C have different refractive indices, the emergent ray is not parallel to the incident ray — unlike a standard glass slab where both outer media are the same (air). Examiners expect this distinction.
- For part (b)(ii), a normally incident ray has angle of incidence = 0°, so angle of refraction = 0° — it goes straight through. This is a standard result from Snell's law.