📚 CBSE Grade-10 Study Guide Open in the Study Guide single page app →
HomeScience

Science — CBSE Class 10 board question

Q1. [5]
Answer the following :
  1. (i) Give reason why carbon can neither form C⁴⁺ cations nor C⁴⁻ anions but form covalent compounds.
  2. (ii) What is homologous series of carbon compound ? Write the molecular formula of any two consecutive members of homologous series of aldehydes.
  3. (iii) Draw the structure of the molecule of cyclohexane (C₆H₁₂).
Previously asked in CBSE board exam
2024 31/2/1 Q34(a)
Generated by claude-sonnet-4-6 · 2026-06-15 06:50 · grounding rag
Model Answer

(i) Carbon has 4 valence electrons. To form C⁴⁺, it would need to lose 4 electrons, requiring a very large amount of energy. To form C⁴⁻, it would gain 4 electrons, but it would be difficult to accommodate 4 extra electrons on the small carbon nucleus — both are energetically unfavourable. Instead, carbon shares its 4 valence electrons with other atoms, forming 4 covalent bonds, which is much more stable.

(ii) A homologous series is a series of carbon compounds having the same functional group and similar chemical properties, where each successive member differs by –CH₂– (molecular mass difference of 14 u).

Two consecutive members of the aldehyde homologous series:

(iii) Structure of Cyclohexane (C₆H₁₂):

$$\begin{array}{c}
\text{Each carbon in the ring is bonded to 2 H atoms}\\[4pt]
\underset{H_2}{\overset{H_2}{C}}\!-\!\underset{H_2}{\overset{H_2}{C}}\text{ (hexagonal ring)}
\end{array}$$

Structural representation:

Each carbon carries 2 hydrogen atoms in a six-membered ring:

```
CH₂—CH₂
/ \
CH₂ CH₂
\ /
CH₂—CH₂
```

Source: Chapter 4, Sections 4.2.2 and 4.2.5

---

Explanation
If a question refers to an image, map, graph or diagram that is not shown here, open the Study Guide single page app, go to Library and find the actual CBSE question paper. The original papers are also available on the CBSE website: cbse.gov.in.
Previous-year CBSE Grade 10 board exam questions, organised by subject and chapter, each with a model answer — free to read and print.