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Mathematics — CBSE Class 10 board question

Q1. [4]
A brooch is a decorative piece often worn on clothing like jackets, blouses or dresses to add elegance. Made from precious metals and decorated with gemstones, brooches come in many shapes and designs. One such brooch is made with silver wire in the form of a circle with diameter 35 mm. The wire is also used in making 5 diameters which divide the circle into 10 equal sectors as shown in the figure.
Based on the above given information, answer the following questions:
  1. (i) Find the central angle of each sector. [1]
  2. (ii) Find the length of the arc $ACB$. [1]
  3. (iii) Find the area of each sector of the brooch. [2]
Previously asked in CBSE board exam
2025 30/1/1 Q37
Generated by claude-sonnet-4-6 · 2026-06-15 10:36 · grounding stimulus
Model Answer

Given: Diameter = 35 mm, so radius $r = \frac{35}{2}$ mm. The circle is divided into 10 equal sectors.

(i) Central angle of each sector:

$$\theta = \frac{360°}{10} = \mathbf{36°}$$

(ii) Length of arc ACB:

Arc ACB spans 2 sectors (as it covers 2 equal parts).

$$\text{Length} = \frac{2 \times 36}{360} \times 2\pi r = \frac{72}{360} \times 2 \times \frac{22}{7} \times \frac{35}{2}$$

$$= \frac{1}{5} \times 110 = \mathbf{22 \text{ mm}}$$

(iii) Area of each sector:

$$\text{Area} = \frac{\theta}{360°} \times \pi r^2 = \frac{36}{360} \times \frac{22}{7} \times \frac{35}{2} \times \frac{35}{2}$$

$$= \frac{1}{10} \times \frac{22}{7} \times \frac{1225}{4} = \frac{1}{10} \times \frac{26950}{28} = \frac{2695}{28} \approx \mathbf{96.25 \text{ mm}^2}$$

Source: Areas Related to Circles, Sector of a Circle

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Explanation
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