Given: ∠D = ∠Q and ∠R = ∠E, so by AA similarity, △DEF ~ △QRP (D↔Q, E↔R, F↔P).
Corresponding sides: $\dfrac{DE}{QR} = \dfrac{EF}{RP} = \dfrac{DF}{QP}$
Option B states $\dfrac{DE}{PQ} = \dfrac{EF}{RP}$, which is not true (DE corresponds to QR, not PQ).
Answer: B
Since ∠D = ∠Q and ∠R = ∠E, the correct correspondence is D↔Q, E↔R, F↔P, giving △DEF ~ △QRP. Check each option against $\frac{DE}{QR}=\frac{EF}{RP}=\frac{DF}{QP}$: Options A, C, D all hold; Option B wrongly pairs DE with PQ instead of QR.