(D) $\dfrac{1}{12}$
Total outcomes = 36. Favourable outcomes (sum > 10): (5,6), (6,5), (6,6) = 3 outcomes. P = $\dfrac{3}{36} = \dfrac{1}{12}$.
Sums more than 10 means sums of 11 or 12. Only three pairs give these: (5,6) and (6,5) for sum 11, and (6,6) for sum 12. Dividing by 36 total outcomes gives 1/12. Students often forget (5,6) and (6,5) are different outcomes.