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Mathematics — CBSE Class 10 board question

Q1. [2]
Evaluate: $2\sin^2 30° \cdot \sec 60° + \tan^2 60°$.
Previously asked in CBSE board exam
2024 30/2/1 Q23(a) (OR-1)
Generated by claude-sonnet-4-6 · 2026-06-15 10:23 · grounding rag
Model Answer

Using standard values: $\sin 30° = \dfrac{1}{2}$, $\sec 60° = 2$, $\tan 60° = \sqrt{3}$

$$2\sin^2 30° \cdot \sec 60° + \tan^2 60°$$

$$= 2 \times \left(\frac{1}{2}\right)^2 \times 2 + (\sqrt{3})^2$$

$$= 2 \times \frac{1}{4} \times 2 + 3$$

$$= 1 + 3 = \boxed{4}$$

Source: Chapter 8, Section 8.3 (Table 8.1)

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Explanation
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