Option B: $30\sqrt{3}$ m
Using $\tan 60° = \dfrac{h}{30}$, we get $\sqrt{3} = \dfrac{h}{30}$, so $h = 30\sqrt{3}$ m.
This directly applies $\tan(\text{angle of elevation}) = \dfrac{\text{height}}{\text{base distance}}$. The base is 30 m and angle is 60°, so multiply 30 by $\tan 60° = \sqrt{3}$. This mirrors Example 1 of Chapter 9 (where base = 15 m gave $15\sqrt{3}$). Don't confuse with Exercise Q4 (which has the same base but angle 30°, giving a different answer).