Option C: $-1$
Here, $a = 3$, $b = -2$, $c = c$. Discriminant $= b^2 - 4ac = (-2)^2 - 4(3)(c) = 4 - 12c = 16$
$\Rightarrow -12c = 12 \Rightarrow c = -1$
Source: Chapter 4, Section 4.4 Nature of Roots
The discriminant is $b^2 - 4ac$. Substitute the given values and set equal to 16, then solve for $c$. Students often make a sign error with $-4ac$ — be careful that $4 \times 3 \times c = 12c$, giving $4 - 12c = 16$, so $c = -1$.