Answer: D $\dfrac{9}{36}$
Total outcomes = 36. Odd numbers on a die: 1, 3, 5 (3 outcomes). Favourable outcomes (odd, odd) = 3 × 3 = 9. So P = $\dfrac{9}{36}$.
Source: Chapter 14, Section 14.1
When two dice are thrown, total outcomes = 6 × 6 = 36. Each die has 3 odd numbers (1, 3, 5), so favourable outcomes = 3 × 3 = 9. Remember to list sample space systematically as shown in Example 13.