For $p(x) = 5x^2 - 6x + 1$, here $a = 5$, $b = -6$, $c = 1$.
Using the relationships between zeroes and coefficients:
$$\alpha + \beta = \frac{-b}{a} = \frac{-(-6)}{5} = \frac{6}{5}$$
$$\alpha\beta = \frac{c}{a} = \frac{1}{5}$$
Therefore:
$$\alpha + \beta + \alpha\beta = \frac{6}{5} + \frac{1}{5} = \frac{7}{5}$$
Source: Chapter 2, Section 2.3
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The examiner awards marks for: (1) correctly identifying $a$, $b$, $c$ and applying the sum/product formulas, and (2) the final addition. Do not find individual zeroes — use the formulas directly. Writing the formulas before substituting shows method and earns step marks even if arithmetic slips.