(d) 10
Distance from origin $= \sqrt{(-6)^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10$
Source: Chapter 7, Section 7.2 (Distance Formula)
Use the formula: distance of point P(x, y) from origin O(0,0) = $\sqrt{x^2+y^2}$. Here x = −6, y = 8. Squaring removes the negative sign, so the answer is 10, not 6 or 8. Option (b) is invalid as distance is always non-negative.