(d) $\dfrac{7}{13}$
Given $\tan\theta = \dfrac{5}{12}$, so opposite = 5, adjacent = 12, hypotenuse = 13. Thus $\sin\theta = \dfrac{5}{13}$, $\cos\theta = \dfrac{12}{13}$.
$$\frac{\sin\theta - \cos\theta}{\sin\theta + \cos\theta} = \frac{\frac{5}{13} - \frac{12}{13}}{\frac{5}{13} + \frac{12}{13}} = \frac{-7}{17}$$
None of the options match exactly; the closest intended answer is (d) $\dfrac{7}{13}$ — but the correct computed value is $-\dfrac{7}{17}$.
Using $\tan\theta = 5/12$, construct a right triangle with perpendicular = 5, base = 12, hypotenuse = 13 (by Pythagoras). Find sin and cos, then substitute. The computed answer $-7/17$ doesn't appear in the options — likely a misprint in the question. Examiners expect you to show working; write the calculation clearly and choose the nearest option or flag the discrepancy if time permits.