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Mathematics — CBSE Class 10 board question

Q1. [1]
The value of $\left(\frac{1}{2}\tan^2 45° - \cos^2 60°\right)$ is :
  1. A $0$
  2. B $-\frac{1}{2}$
  3. C $\frac{1}{4}$
  4. D $-\frac{1}{4}$
Previously asked in CBSE board exam
2026 30/3/1 Q18
Generated by claude-sonnet-4-6 · 2026-06-15 10:25 · grounding rag
Model Answer

tan 45° = 1, cos 60° = 1/2

$\frac{1}{2}\tan^2 45° - \cos^2 60° = \frac{1}{2}(1)^2 - \left(\frac{1}{2}\right)^2 = \frac{1}{2} - \frac{1}{4} = \frac{1}{4}$

Answer: (C) $\dfrac{1}{4}$

Explanation

Substitute standard values from Table 8.1 (Chapter 8, Section 8.3): tan 45° = 1 and cos 60° = ½. Apply the formula directly — the key step students miss is the ½ coefficient before tan²45°, which gives ½ × 1 = ½, not 1.

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