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Mathematics — CBSE Class 10 board question

Q1. [1]
Curved surface area of a cylinder of height 5 cm is 94.2 cm². Radius of the cylinder is (Take $\pi = 3.14$)
  1. A 2 cm
  2. B 3 cm
  3. C 2.9 cm
  4. D 6 cm
Previously asked in CBSE board exam
2023 30/1/1 Q10
Generated by claude-sonnet-4-6 · 2026-06-15 10:35 · grounding rag
Model Answer

Using CSA of cylinder = $2\pi rh$:

$94.2 = 2 \times 3.14 \times r \times 5$

$r = \dfrac{94.2}{31.4} = 3$ cm

Answer: B) 3 cm

Explanation

Substitute the CSA formula $2\pi rh = 94.2$, plug in $\pi = 3.14$ and $h = 5$, then solve for $r$. The denominator $2 \times 3.14 \times 5 = 31.4$, giving $r = 3$ cm exactly. Watch units and don't confuse CSA with TSA (which adds the two circular bases).

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